Curse

jeffy · May 21, 2005, 07:25 PM // 19:25

I was bored so I just made a little chart. You know that GUILD WARS - QUICK REFERENCE that you get in your box, when you buy guildwars, on the back, there's an attribute point allocation. I was curious how the Attribute level to Total Cost was figured out. So I found out that the attribute Levels are done by pairs(Level 1 and 2 use the same formula). Anywho, Here it is..

Attribute Level:=(x) ////Total Cost:=(y)
1,2 ------------------------------ y=2x - 1
3,4 ------------------------------ y=4x - 6
5,6 ------------------------------ y=6x - 15
7,8 ------------------------------ y=9x - 35
o9,10 ---------------------------- y=13x - 69
11,12 ---------------------------- y=20x -143

I'm not sure if the people used the system, but thats just what I am learning in Algebra. Check my work, do w/e. Plus, I don't find any patterns yet.. but you can do that, try getting #s, 13-20

Willow · May 21, 2005, 09:02 PM // 21:02

(I'm assuming you're in middleschool, possibly early high school, so please don't take offense if you're actually older. That said, hope you're having fun with math!)

The values for 1 through 7 are just your basic triangular number formula, where the xth value in the series is x more than the one before.

I would express it like this:
Y(x)= Y(x-1) + x
Y(0)=0

You can plot that on a graph, but it doesn't have a constant slope.

After that the total cost accelerates- and increases faster than the 1:1 ratio. With a cursory examination, I can't figure out why either. (My guess is just to make high attributes cost even more, not adherence to any particular pattern.)

Willow · May 21, 2005, 09:08 PM // 21:08

One more thing to add: it's possible to make a linear formula that will describe ANY two points.

For example, you have the line
1,2: 7=2x-1
Which is correct for those two points.

But suppose I take (x=1, y=1), and (x=12, y=97). Both are valid points on our graph, and can be connected an easily derived formula that describes only those two points, and none of the others (but it involves some fractions that make it a little less intuitive than the easy whole numbers in your formulae.)

jeffy · May 22, 2005, 04:28 AM // 04:28

Yeah im in 7th grade taking algebra.. i only understand some of your concepts ><

Serafita Kayin · May 22, 2005, 04:33 AM // 04:33

I think it can be expressed as an exponential...

Good work guys, when I'm not as sick I'll help you work on it some more...

JjK · May 22, 2005, 04:35 AM // 04:35

With these, make sure you don't consider skill points you get from quests/missions. Those don't apply here.

exp to next skill point = 1400 + 600x
where x is the number of the next skill point you'll earn through experience
ex. To get your 60th skill point, you'll need to gain 1400 + 600*60 = 37400 experience after getting enough exp to earn your 59th skill point.

total exp = 300xx + 1100x - 1400
where x is the number of the next skill point you'll earn through experience
When you start to work towards earning your 60th skill point, you'd have already earned 300*60*60 +1100*60 - 1400 = 1,144,600 experience

number of skill points you have earned through experience = (-55 + sqrt(7225 + 3*your total exp)) / 30 - 1

no. of the next skill point you'll earn, Total amount of Exp, Exp to earn the next skill point
1 0,000 2000
2 2,000 2600
3 4,600 3200
4 7,800 3800
5 11,600 4400
6 16,000 5000
7 21,000 5600
8 26,600 6200
9 32,800 6800
10 39,600 7400
11 47,000 8000
12 55,000 8600
13 63,600 9200
14 72,800 9800
15 82,600 10400
16 93,000 11000
17 104,000 11600
18 115,600 12200
19 127,800 12800
20 140,600 13400
21 154,000 14000
22 168,000 14600
23 182,600 15200
24 197,800 15800
25 213,600 16400
26 230,000 17000
27 247,000 17600
28 264,600 18200
29 282,800 18800
30 301,600 19400
31 321,000 20000
32 341,000 20600
33 361,600 21200
34 382,800 21800
35 404,600 22400
36 427,000 23000
37 450,000 23600
38 473,600 24200
39 497,800 24800
40 522,600 25400
41 548,000 26000
42 574,000 26600
43 600,600 27200
44 627,800 27800
45 655,600 28400
46 684,000 29000
47 713,000 29600
48 742,600 30200
49 772,800 30800
50 803,600 31400
51 835,000 32000
52 867,000 32600
53 899,600 33200
54 932,800 33800
55 966,600 34400
56 1,001,000 35000
57 1,036,000 35600
58 1,071,600 36200
59 1,107,800 36800
60 1,144,600 37400

70 1,545,600 43400
80 2,006,600 49400
90 2,527,600 55400
100 3,108,600 61400
110 3,749,600 67400
120 4,450,600 73400
130 5,211,600 79400
140 6,032,600 85400
150 6,913,600 91400
160 7,854,600 97400
170 8,855,600 103400
180 9,916,600 109400
190 11,037,600 115400
200 12,218,600 121400
210 13,459,600 127400
220 14,760,600 133400
230 16,121,600 139400
240 17,542,600 145400
250 19,023,600 151400
260 20,564,600 157400
270 22,165,600 163400
280 23,826,600 169400
290 25,547,600 175400
300 27,328,600 181400
310 29,169,600 187400
320 31,070,600 193400
330 33,031,600 199400
340 35,052,600 205400
350 37,133,600 211400
360 39,274,600 217400
370 41,475,600 223400
380 43,736,600 229400
390 46,057,600 235400
400 48,438,600 241400
410 50,879,600 247400
420 53,380,600 253400
430 55,941,600 259400
440 58,562,600 265400
450 61,243,600 271400

-The Fianna

jeffy · May 22, 2005, 04:42 AM // 04:42

What level would you be when you gain 450 skill points ? 20 ?

Spartan2 · May 22, 2005, 04:43 AM // 04:43

This would probably be easier to describe using the whole Tn=(T1^n)+y or whatever that is called. Just went over that crap in PreCal and as you can guess, I did not pay attention, and I am pretty sure that equation is not correct either.

JjK · May 22, 2005, 04:44 AM // 04:44

The above is correct, make a char and test it.

I believe as of now, 230 is the most

Spartan2 · May 22, 2005, 04:46 AM // 04:46

JjK, I was commenting on the fact that my supposed equation was not correct, not yours.

JjK · May 22, 2005, 04:47 AM // 04:47

/appologize

shady_knife · May 22, 2005, 07:54 AM // 07:54

Quote:

Originally Posted by jeffy

Yeah im in 7th grade taking algebra.. i only understand some of your concepts ><

only some? im in yr 11 and didnt understand a word..... but i hate maths.

Willow · May 22, 2005, 03:57 PM // 15:57

Well, I'll try to explain what I was doing a little simpler:

The triangular number pattern is just a bunch of linked numbers.

Here's a simpler pattern:
3, 7, 11, 15, 19
Every number is 4 more than the number before it.
Since 3 is the first number, we call it n=1. 7 is second, so it's n=2, and so on. In this case, the value of each number in the series is called X(n).

So:
3 = x(1)
7 = x(2)
11= x(3)
15= x(4)
19= x(5)

We can say that x(n)=x(n-1) +4.
So if you're looking for the value of say, the 6th number you know that:
x(6)= x(5) +4
And from our chart we already have x(5), which is 19. So X of 6 is 23.
However, from that formula "x(n)=x(n-1) +4" we don't have the whole story- you need a reference point, so we add in
x(1)=3

-

For the triangular number function, each new number in the series increases by one more than the last one (so first +1, then +2, then +3, etc.)

So I posted this formula:
Y(x)= Y(x-1) + x
Y(0)=0

Which is in terms of Y and X, not X and n. But that doesn't matter too much, one can use whatever letters they want for variables. X and n are fairly traditional for functional mathematics (what I'm talking about), and X and Y are used for Cartesian graphs (which you're talking about, even if you don't know it yet.)

By using those same steps above, you should be able to figure out every value (Y's) for any number of steps in the pattern (the X's)

(I'll talk a little bit more about linear formulae later. Let me know which parts confuse you and which are interesting- I think it's great that you're into math, and I'd like to lend a hand.)